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SAT Prep Course @satprepcourse.bsky.social
Jul 12, 06:18 AM

SAT Advanced Math Question: Given the system: 8x + y = -11 2x² = y + 341 The graphs intersect at point (x, y). What is a possible value of x? Correct Answer: -15 #SAT #SATMath #SATPrep #SystemOfEquations #AdvancedMath #Algebra #SATHacks #TestPrep #harvard

🎤 Whisper Transcript (en) ⏱ 62s

"When using the substitution method, how do you choose which variable to isolate first? Take this system. 8x plus y equals negative 11, and 2x squared equals y plus 341. The speed trap is trying to isolate x. That creates an ugly fraction that makes your next step a nightmare. Instead, find the variable that appears without an exponent in both equations. Here, that's y. Isolate it on both sides to get these two flat equations. Because you prioritize the winnier variable, you skip the fractions completely, and move everything to one side to combine like terms. This gives you an equation with massive, intimidating numbers. But don't panic. Just divide the entire equation by 2 to shrink the coefficients. Now it's much easier to factor, revealing your two possible roots, negative 15 and 11. Because you kept the algebra flat and avoided messy squares, you can instantly match negative 15 to the correct option and move on in seconds."

💬 Discussion

SAT Prep Course @satprepcourse.bsky.social · Jul 10, 03:37 PM

SAT Advanced Math Question: Given the system: 8x + y = -11 2x² = y + 341 The graphs intersect at point (x, y). What is a possible value of x? Correct Answer: -15 #SAT #SATMath #SATPrep #SystemOfEquations #AdvancedMath #Algebra #SATHacks #TestPrep #harvard

<div class="border-l-2 border-slate-800/60 pl-4 py-2 mt-3 ml-2"> <div class="flex items-start gap-2.5"> <!-- Avatar --> <img src="https://cdn.bsky.app/img/avatar/plain/did:plc:7ulqbhf7k2cuufu3ybuncipw/bafkreic7cswkr7yfsqou2hlcijg4ohukxoklbminh3zfmhwnsb2rzlafia" class="w-6 h-6 rounded-full shrink-0 border border-slate-800" /> <!-- Comment Content --> <div class="flex-1 min-w-0"> <div class="flex items-center gap-2 mb-1"> <span class="text-xs font-bold text-slate-300">SAT Prep Course</span> <span class="text-[10px] text-slate-500">@satprepcourse.bsky.social</span> <span class="text-[9px] text-slate-600">· Jul 10, 03:38 PM</span> </div> <p class="text-xs text-slate-350 leading-relaxed break-words">Step-by-step solution explained clearly: • Solve for y from the first equation: y = -8x - 11 • Substitute into the second: 2x² = (-8x - 11) + 341 • Simplify: 2x² + 8x - 330 = 0 • Divide by 2: x² + 4x - 165 = 0 • Factor: (x + 15)(x - 11) = 0 • Solutions: x = -15 or x = 11</p> </div> </div> <!-- Replies --> </div>