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Holistiक्षा
@holistiksha.bsky.social
· Jul 6, 11:05 AM
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<span class="text-xs font-bold text-slate-300">Holistiक्षा</span>
<span class="text-[10px] text-slate-500">@holistiksha.bsky.social</span>
<span class="text-[9px] text-slate-600">· Jul 6, 11:05 AM</span>
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<p class="text-xs text-slate-350 leading-relaxed break-words">Solution:
→ The 64° angle is b/w the tangent at T &amp; chord TA
→ Since AB is the diameter, ∠ATB = 90°, making the angle b/w the tangent &amp; TB equal to 26° via adjacent angles on the straight tangent line
→ Applying the alternate segment theorem gives ∠TAB = 26° &amp; ∠ABT = 64°.</p>
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<span class="text-xs font-bold text-slate-300">Holistiक्षा</span>
<span class="text-[10px] text-slate-500">@holistiksha.bsky.social</span>
<span class="text-[9px] text-slate-600">· Jul 6, 11:05 AM</span>
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<p class="text-xs text-slate-350 leading-relaxed break-words">→ In △TBP, ∠TBP = 180° - 64° = 116° and ∠PTB = 26°, so angle X at P equals 38°.</p>
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